please help i give medals! write a function rule for the table given below x | 0 | 1 | 2 | 3 | 4 | 5 | y |-3 | -2 | -1 | 0 | 1| 2 | a y=x+3 b y= -2x c y= x-3 d y= x+1
select any two points as (0,-3) and (1,-2)
then are you know what the method that used for form a straight line eqution bu using two points?
no idea @esamalaa
\[\frac{ y-y _{1} }{ x-x _{1} }=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\]
so would that be a, b, c, or d? D:
@esamalaa ?? a b c or d?
x | 0 | 1 | 2 | 3 | 4 | 5 | y |-3 | -2 | -1 | 0 | 1 | 2 | can you see a common difference between x and y?
@unklerhaukus i mean i guess top is positive bottom is negative im not sure to be honest
both x and y are increasing, right?
yes
when x increases by one each time, how much does y increase?
by -1
are you sure about that?
OHH i think i get it now they both are increasing by 1, so the awnser would be d y=x+1 ?
they are both increasing by the same amount (one) each time, but they start at different values
what is the difference between the starting values?
3 or -3
yeah -3
in fact the only difference between x and y is that y is three less than x , right?
yes
Which of the options corresponds with the statement `y is three less than x` a) y=x+3 b) y= -2x c) y= x-3 d) y= x+1
ah i think i see so it would be c x-3 for three less than?
you can try that solution out y= x-3 when x =0 y= 0-3 y= -3 which fits the first column on the table x | 0 | y |-3 |
what about the second column, for x=1 y= x-3 = 1-3 = ? x | 0 | 1 | y |-3 | ? | does this equation work?
|1| |-2| i beleive so if you do -3-1=-2?
good, lets lets one more point , just to be sure what do you get if you sub x=5 into y=x-3
*lets test
|5| |2| -3-5=2
thanks so much man!
careful * x=5 into y = x -3 y = 5 -3 = 2
so the answer would be C
yers
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