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Mathematics 19 Online
OpenStudy (anonymous):

use the grouping to simplify the following x^2+4x+2x+8 A. (x+4)(x+8) B. (x+4)(x+2) C. (3x+4) D. 7x+8

HanAkoSolo (jamierox4ev3r):

With this problem, it seems like you're factoring. What you have to do is to first add like terms together. Can you find the two of them? @trever74

OpenStudy (anonymous):

x^2+6x+8 ?

HanAkoSolo (jamierox4ev3r):

right, that's good so far. Then, find one number that factors into 8 and adds to 6. What I'm trying to say is, we should factor the 8 first. The possible factors are: 1 8 2 4 Out of these two sets, which one will also add up to 6?

HanAkoSolo (jamierox4ev3r):

Trever you there bruh?

OpenStudy (anonymous):

confused lol

OpenStudy (triciaal):

x^2 = x*x you can eliminate C and D what are the factors of 8 that when you add you get 6 4, 2 x^2 + 4x + 2X + 8 x(x+2) + 4(x +2) (x +4)(x+2)

OpenStudy (anonymous):

ohh okay i seee now

OpenStudy (anonymous):

thanks

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