Question

help with two 8th grade math questions!
medal and fan reward!
Thanks!
question attached below.

Answer 1

help!

Answer 2

@SiennaSurfer

Answer 3

For number 1 you have 3 and 4 mixed up

Answer 4

so just switch those up?

Answer 5

d and a?

Answer 6

You need to solve for the variable BEFORE you substitute it into the the other equation.

So yes just switch D and A

Answer 7

And for number 2)

x = 2y - 2, 3x - y = 14

So sub in x = 2y - 2 for 'x' in the second equation

3x - y = 14
becomes

3(2y - 2) - y = 14

distribute

6y - 6 - y = 14

Combine like terms

5y - 6 = 14

Add 6 to both sides

5y = 20

Divide both sides by 5

y = ?

Answer 8

4

Answer 9

so which one is my answer?

Answer 10

Well as you can see we solved y = 4 so that is your y variable in the ordered pair..

Now we solve for 'x'....plug 4 in for every 'y' you see in one equation and see what 'x' comes out to...

Answer 11

6

Answer 12

so its 6,4?

Answer 13

Correct!

Answer 14

thanks!