Question

If the area of a rectangle 16s2t and the length is 8st2, what would the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

Answer 1

2st

2/st

2s/t

t/2s

Answer 2

@jdoe0001

Answer 3

@Mertsj

Answer 4

nevermind, it's C

Answer 5

\(\bf Area = Length\cdot Width\qquad Area=16s^2t\qquad Length=8st^2
\\ \quad \\
Area = Length\cdot Width\implies \cfrac{Area}{Length}=Width\implies \cfrac{16s^2t}{8st^2d}=Width\)