I thought after you distribute the 3, you have to add 18 and 3 but then my teacher said you dont , you just then solve for x...im really confused heres the problem, it would be GREAT if someone can explain everything to me
y=-2x+6
3y-x+3=0

Question

I thought after you distribute the 3, you have to add 18 and 3 but then my teacher said you dont , you just then solve for x...im really confused heres the problem, it would be GREAT if someone can explain everything to me 
 y=-2x+6
3y-x+3=0

jim_thompson5910 · Answer

Start with the equation 3y-x+3=0

Now replace every copy of y with -2x+6 

this is because y = -2x + 6 is the first equation

jim_thompson5910 · Answer

so,

3y-x+3=0

3(-2x+6)-x+3=0

3(-2x) + 3(6) - x + 3 = 0

-6x + 18 - x + 3 = 0

-7x + 21 = 0

I'll let you finish in solving for x

jim_thompson5910 · Answer

Tell me what you get

anonymous · Answer

first you have to change the second equation to make it 3y=-x-3 then u add them

anonymous · Answer

Oh okay so my answer is (3,0)

jim_thompson5910 · Answer

very good, (3,0) is correct