Question

Identify the vertex for the graph of y = −3x2 − 6x + 4.

(1, 13)

(−1, 13)

(1, 7)

(−1, 7)

Answer 1

Is it C?

Answer 2

no

Answer 3

Then it has to be A because I know X is 1

Answer 4

first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\)
and so \(y = -3 x^2-6 x+4\) is \(-\frac{-6}{2\times (-3)}=1\)

Answer 5

oops i meant \(-1\)! !!

Answer 6

\[-\frac{-6}{2\times (-3)}=-1\]

Answer 7

so what is Y?