graph the function and state the vertex, axis of symmetry, and the intercepts, if any.
f(x)=x^2-6x+8
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OpenStudy (anonymous):
This is easy.
OpenStudy (anonymous):
First you have to find the "zeroes" or the x-intercepts.
OpenStudy (anonymous):
so do i replace all x's with 0?
OpenStudy (anonymous):
No
OpenStudy (anonymous):
You have to replace Y AS 0, because the x-intercept is what x is when y = 0.
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OpenStudy (anonymous):
So we have 0 = x^2 - 6x + 8
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Now we have to factor.
OpenStudy (anonymous):
do you have to get rid of the ^2?
OpenStudy (anonymous):
No
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OpenStudy (anonymous):
im sorry math is not my strong suit, this stuff really confuses me =(
OpenStudy (anonymous):
Well, later on we do.
OpenStudy (anonymous):
It's alright.
OpenStudy (anonymous):
So we have to find out the squares of the first and last terms, do you know what they are?
OpenStudy (anonymous):
Well we get x from the first term, and we use 8 as our last term.
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OpenStudy (anonymous):
So 8 * x = 8x so we need to find out what the factors of 8 are that add up to the MIDDLE TERM 6x.
OpenStudy (anonymous):
Can you state some factors of 8?
OpenStudy (anonymous):
1,2,4,8
OpenStudy (anonymous):
Right, so let's try 1 and 8.
OpenStudy (anonymous):
Remember, they both have to add up to 6 and multiply to 8.
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OpenStudy (anonymous):
1 x 8 = 8. But 1 + 8 = 9. We're looking for a 6, not a 9.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
2 and 4
OpenStudy (anonymous):
Yes, you got it!
OpenStudy (anonymous):
So we replace 6x with 4x and 2x.
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OpenStudy (anonymous):
0= x^2-(4x+2x)+8?
OpenStudy (anonymous):
Uh-oh
OpenStudy (anonymous):
?
OpenStudy (anonymous):
I made a mistake, sorry. We need 2 things that add up to -6 and multiply to 8.
OpenStudy (anonymous):
so -2 and 4
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OpenStudy (anonymous):
-2 and -4*
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
So we have 0= x^2 - 4x - 2x + 8?
OpenStudy (anonymous):
Now we're going to separate the first two terms and the last two terms with a parenthesis:
OpenStudy (anonymous):
0 - (x^2 - 4x) - (2x + 8)
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
We have to find out the GCF or greatest common factor of each parenthesis, can you tell what the GCF of the first parenthesis is?
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
No, look again. Remember it can be a variable.
OpenStudy (anonymous):
x
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OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
So we're going to work backwards with the first parenthesis:
x(x^2 - 4x)
We are DIVIDING x by each term, since we're working backwards
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
So basically we're removing 1 x from all the parenthesis:
x(x^2 - 4x)
Removing 1 x from x^2 would give us a regular x.
x(x - 4x)
And removing x from -4x will give us a -4.
x(x - 4)
So we finished our first parenthesis.
OpenStudy (anonymous):
Can you tell me the GCF of the 2nd parenthesis?
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
so it would be 2(2x+4)?
OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
2(x+4)*
OpenStudy (anonymous):
You made a mistake, remember that your 2x is a NEGATIVE 2x.
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OpenStudy (anonymous):
so 2(-x+4)?
OpenStudy (anonymous):
No, your GCF will be a -2.
OpenStudy (anonymous):
You want to keep x positive.
OpenStudy (anonymous):
-2(x+4)
OpenStudy (anonymous):
Yes, almost perfect. Remember 8 / -2 = -4, not 4.
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OpenStudy (anonymous):
-2(x-4)
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
So we have 0 = x(x - 4) - 2(x - 4)
We can combine x - 4, because they're the same(If these terms aren't the same, then you know you made a mistake). And we have to combine the terms outside of both parentheses.
So we have (x - 2)(x - 4)
Do you understand how I got (x - 2)?
OpenStudy (anonymous):
no =(
OpenStudy (anonymous):
oooh wait! the x and -2 outside of the parentheses!
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
You need to combine those.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
So now that we figured out that form we can finish the problem.
0 = (x - 2)(x - 4)
OpenStudy (anonymous):
We have to break each parenthesis down and add a '= 0' to it.
So for the first parenthesis:
0 = x - 2
Now we just figure out what x is by adding 2 to both sides.
2 = x
x = 2
Can you figure out the 2nd parenthesis out?
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OpenStudy (anonymous):
x=4
OpenStudy (anonymous):
Yes, so we have: x = 2 and x = 4. We know that the parabola crosses the x-axis at 2 and 4.
OpenStudy (anonymous):
Those are your x-intercepts.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
The y-intercept is what y is when x = 0. So we can go back to the original equation and change all the x's to 0.
f(x) = (0)^2 - 6(0) + 8
f(x) = 0 - 0 + 8
f(x) = 0 + 8
f(x) = 8
So our y-intercept is 8.
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OpenStudy (anonymous):
would it be (0,8) for the y intercept and (2,0) (4,0) for x?
OpenStudy (anonymous):
Yep.
OpenStudy (anonymous):
ok =)
OpenStudy (anonymous):
Now we have to find the vertex.
OpenStudy (anonymous):
The formula for the vertex is -b/2a.
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OpenStudy (anonymous):
Your equation is in the form of a^2 - bx + c
So what is 'a' and 'b'?
OpenStudy (anonymous):
x and -6
OpenStudy (anonymous):
Not quite, the "a" has to be a number.
OpenStudy (anonymous):
1
OpenStudy (anonymous):
x by itself can also be what?
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OpenStudy (anonymous):
Yes, that's it.
OpenStudy (anonymous):
So we have 1 and -6.
We can plug these into our equation:
-1/2(-6)
Can you figure it out?
OpenStudy (anonymous):
My bad it's:
-6/2(-1)
OpenStudy (anonymous):
6/-2
OpenStudy (anonymous):
-3
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OpenStudy (anonymous):
Ugh, I made another mistake it's
6/2(1)
6/2
3
OpenStudy (anonymous):
3 is the x-value of our vertex. We can plug it into our equation to get the y-intercept.
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
f(x) = x^2 - 6x + 8
f(x) = (3)^2 - 6(3) + 8
OpenStudy (anonymous):
f(x) = (3)^2 - 6(3) + 8
f(x) = 9 - 18 + 8
f(x) = -9 + 8
f(x) = -1
So the y-value of our vertex is -1.
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OpenStudy (anonymous):
yes i got -1
OpenStudy (anonymous):
vertex is (3,-1) ?
OpenStudy (anonymous):
So our vertex is: (3, -1). Our y-intercept is (0, 8), and our x-intercepts are (2, 0) and (4, 0).
OpenStudy (anonymous):
Yes, it's (3, -1)
OpenStudy (anonymous):
The axis of symmetry will be our x-value, or 3.
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OpenStudy (anonymous):
oh ok awesome!
OpenStudy (anonymous):
That's everything, that's how you figure it out by looking at it from our equation. You can graph it here:
https://www.desmos.com/calculator
And you will get all the instant answers.