Question

(2m^3)^0(3m^6)^-1
its simplifying,the answer is 1/3m^6
i just dont know how to get that

Answer 1

\[(2m^3)^0*(3m^6)^{-1}\]
Ok we know that anything to the power of 0 =1 so for instance \(x^0=1\)
Hence we can conclude that \((2m^3)^0=1\)
Another property is that any number to the power of a negative value means *flip me* so \(x^{-1}=\large\frac{1}{x}\) or \(x^{-2}=\large\frac{1}{x^2}\)
so therefore \[(3m^6)^{-1}=\frac{1}{3m^6}\]
Therefore we have \[1*\frac{1}{3m^6}=\frac{1}{3m^6}\]

Answer 2

wait why does it say "math processing error"

Answer 3

wtf is wrong with os???

Answer 4

http://puu.sh/7jmmL.png

Answer 5

Take a look at that link ^

Answer 6

oh ok thnkss

Answer 7

ooo i get it now thanxx