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Solve this system of equations by using substitution. 3x + y = 1 y = x + 5
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replace \(y\) in the first equation by \(x+5\) and solve \[3x+x+5=1\] for \(x\)
it has to be two points like this (___,___)
It will be once you solve it, 3x + x + 5 = 1, solve for x
i dont know how to do it
3x + x = ?
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4x
4x + 5 = 1 Subtract 5 from both sides, whats that?
4x=-4
Do you know how to isolate x?
um like devide both sides
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Yes, 4x = -4 /4 /4 x = ?
x=-1
so i know (-1,___)
Now plug in -1 for x and solve for y, y = -1 + 5
Solved? I have to leave right now.
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k ty
yw, you're suppose to get (-1,4) 3(-1) + 4 = 1 -3 + 4 = 1 1 = 1 <-- therefore this works
yes i got that
Ok. Bye.
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