Question

F (x)=3-2x+x^2 find f(-3)

Answer 1

is f(x)= F(x)? or we have to use integrals?

Answer 2

I'm assuming we are simply supposed to evaluate \(f(x) = 3-2x+x^2\) at \(x = -3\):

\[f(-3) = 3 - 2(-3) + (-3)^2 = \]

Answer 3

0 is the answer

Answer 4

F(-3)=3+6+9=18

Answer 5

@faisalalif1999 how on earth did you come up with 0 from the expression
\[f(-3) = 3 -2(-3) + (-3)^2\]\[(-2)*(-3) = 6\]\[(-3)^2 = (-3)*(-3) = 9\]\[f(-3) = 3-2(-3)+(-3)^2 = 3+6+9 = 18\]

Answer 6

Reason..
about the question if x = -3..
F(-3) = 3 - 2(-3) + (-3)^2
F(-3) = 3 - (-6) + 9 >> (-3)^2 = 9 // 3 x 3 = 9 // 2(-3) = 6
F(-3) = 3 + 6 + 9 = 18
F(-3) = 18...
This would be the answer of F(-3)...

Answer 7

f = -3

Answer 8

sorry, x = 18 lol