Question

4(4k+2)-8(k-1)>3(2k+3)-2 a little line under the >

Answer 1

sorry i edited it

Answer 2

the last one someone helped me with i got wrong

Answer 3

\[4(4k+2)-8(k-1)\ge 3(2k+3)-2\]

Answer 4

yes thats correct

Answer 5

\[16k+8-8k+8\ge6k+9-2\]

Answer 6

\[8k+18\ge 6k+7\]
\[2k \ge -11\]

Answer 7

\[k \ge\frac{-11}{2}\]

Answer 8

omg thanks so much your a life saver

Answer 9

yw. And you need to learn to solve these simple problems by yourself, sweetheart.

Answer 10

i got it wrong it keeps saying its wrong :(

Answer 11

Check the rules for entry. Maybe it is supposed to be a decimal or a mixed number.

Answer 12

No. I made a mistake.

Answer 13

\[8k+16\ge6k+7\]
\[2k \ge -9\]

Answer 14

\[k \ge -\frac{9}{2}\]

Answer 15

Was that right?