Question

Show that limit of |1-3x| = 5 as x->2

Answer 1

Well as we approach 2...(i usually just plug in 2 unless you see explicitly it won't work) so I would plug in 2 here for 'x'

|1 - 3(2)| = 5
|1 - 6| = 5
|-5| = 5

Does that make sense? if not, you can always graph your function and see that at x = 2 you approach 5 on the function line

Answer 2

now find delta

Answer 3

lol, epsilon delta definition ... i dont know why i hate that one soo much

Answer 4

i did it, just need to verif my answer... Do it please