This is an example question and I am confused on how they solved the question. It's lesson tittle is solving quadratics by factoring. x^2-7x+12=0 x=3 and x=4
if we take some generic factors: (x+a)(x+b) and multiply them together, what do we get?
x^2 +ab right??
(x+a)(x+b) ... if FOIL rings a bell: x^2 +ax + bx + ab so: x^2 + (a+b)x + ab, has to equal, x^2 -7x + 12 in order for these to be the exact same thing, then: a+b = -7 ab = 12
since 12 is a positive number, a,b are the same sign since -7 is negative, the signs of a,b have to be negative what are the factors of 12? 1,12 .. adds to 13 2,6 .. adds to 8 3,4 .. adds to 7, this has to be the correct set then
so, let a = -3, and b = -4 the roots are then, -3, -4
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