Question

Use the quadratic equation y = x^2 + 3x – 10.

Where does the vertex of the parabola lie?

A.
below the x-axis

B.
above the x-axis

C.
on the y-axis

D.
on the x-axis

Answer 1

Familiar with completing the square?

Answer 2

No

Answer 3

Umm how about factoring?

Answer 4

yes

Answer 5

\[y=x^2+3x-10\]
Now we need to find 2 numbers that when you add them together it equals 3 and when you multiply it equals -10
5 and -2
5-2=3
5*-2=-10
\[x^2-2x+5x-10=0\]
\[(x^2-2x)+(5x-10)=0\]
\[x(x-2)+5(x-2)=0\]
\[(x-2)(x+5)=0\]
\[ x=2 \text{ and } x=-5\]

Do you follow this so far?

Answer 6

Yes, I understand so far :)

Answer 7

its 2 and 5