Can someone help me with this?

(log2)4+(log2)2-(log2)8

the 2s in parenthesis are little, if that makes sense? If not I can try to clarify. Thanks! :)

Question

Can someone help me with this? 

(log2)4+(log2)2-(log2)8

the 2s in parenthesis are little, if that makes sense? If not I can try to clarify. Thanks! :)

anonymous · Answer

is it squared or are the little twos on the bottom?

anonymous · Answer

on the bottom

jdoe0001 · Answer

hmm what are you supposed to do with $\bf log_24+log_22-log_28\quad ?$

anonymous · Answer

What do you mean, like the directions?

anonymous · Answer

yeah the directions.

jdoe0001 · Answer

hmm I assume is just a simplification?

anonymous · Answer

It says to write each expression as a single logarithm.

jdoe0001 · Answer

ohh

anonymous · Answer

would it be (log2)-8    (times negative 8 not minus 8)

anonymous · Answer

Im not 100% Sure ...

jdoe0001 · Answer

http://www.chilimath.com/algebra/advanced/log/images/rules%20of%20exponents.gif <--- use rule 1 and 2 listed there then

anonymous · Answer

(log2)8 * (log2) 8/1
would that be right @jdoe0001

jdoe0001 · Answer

well... close

so.. what did you get @cellogirl ?

anonymous · Answer

(log2)1?

jdoe0001 · Answer

$\bf log_24+log_22-log_28\implies log_28-log_28\implies log_2\cfrac{8}{8}\implies log_21$
yeap

anonymous · Answer

Thank you so much!

jdoe0001 · Answer

yw