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Two dice are tossed. What is the probability that their sum will be 3, given that exactly one face shows 2?
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if one face shows a 2, there are the following possibilities \[(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(2,1),(2,3),(2,4),(2,5),(2,6)\]
how many of those give you a total of 3?
ooh, i didn't read carefully , it said "EXACTLY face shows a 2"\[(1,2),(3,2),(4,2),(5,2),(6,2),(2,1),(2,3),(2,4),(2,5),(2,6)\] gotta get rid of the double twos
Would it be 1/36? or do I have to divide 2/36?
let the first dice be the one that shows 2, without loss of generality the second dice can show any number except 2. it can show 1,3,4,5,or 6 of these possibilities, only the first one will result in a sum of 3. thus, the chance is 1/5
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