Question

integral of (4x-2)^3

Answer 1

u-sub, did you try that?

Answer 2

oops my problem is actually integral of (4-2x)^3

Answer 3

sorry :| but yes @sourwing but some how I'm getting stuck on this particular integral

Answer 4

i am getting the answer -(1/8)(4-2x)^4 but my book has another answer

Answer 5

there are two ways you can do this -
the lengthy way - break (4-2x)^3 using (a-b)^3 and apply integral over each part

Answer 6

that's correct.

Answer 7

the short way - use substitution by assuming y = 4-2x

Answer 8

what does the book have?

Answer 9

the book has...

Answer 10

can you simplify (-1/8) (4-2x)^4 ?

Answer 11

(-1/8) (4-2x)^4 = (-1/8)(2)^4 (2-x)^4 = -2(2-x)^4

Answer 12

your book simplified the integral. The two are still the same

Answer 13

@sourwing right: they just took the 2 as common from the part (4-2x) to write 2(2-x)

Answer 14

ahhh i figured that was the case i just wasn't totally sure if i could pull out the 2!