Question

Use basic identities to simplify to sines and cosines:
(sinx/cot^2x)-(sinx/cos^2x)

Answer 1

your attempt?

Answer 2

ive made several but i keep ending up with (sin^3-sin)/cos^2 but that doesnt look right...

Answer 3

\(tan =\dfrac{1}{cot}\rightarrow\)the first term is \(sin*tan^2\) ok?

Answer 4

tan =\(\dfrac{sin}{cos}\rightarrow\) the second term is \(\dfrac{1}{cos}*tan\)

Answer 5

ohh i see i didnt split the second term into thatbut that makes sense

Answer 6

i think i got it from ther thank you so much!

Answer 7

ok