Question

HOW DO I SOLVE ((K+6)/(K+3))>1. PLEASE SHOW DETAILS.

Answer 1

((K+6)/(k+3)>1

Cross multiply

K+6>k+3
K-k+3>0
Where k is cancelled out
So in this case since k is found at both numerator and denominator

If k=0 2>1
The lesser the value of k the higher it gets
If k=-2.99
301>1
K cant be -3 the denominator will be zero making it undefined.

And as the higher the k .. The value equals to 1
If k=100000 youll get something a little bit greater than one
It wont be equal to one as k gets higher but only gets closer to it. "asymptotic"


So the values of k
K>3

Answer 2

K>-3 I should say sorry