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OpenStudy (anonymous):
A baseball is thrown straight up at 15m/s. How high will it go?
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OpenStudy (anonymous):
I am thinking if there's any use trying to explain it..
OpenStudy (anonymous):
Do you have any ideas?
OpenStudy (anonymous):
i do not know how to solve the problem... how do you solve it?
OpenStudy (anonymous):
It is a physics problem/equation
OpenStudy (anonymous):
try to do it by yourself: Where will have a zero speed?
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OpenStudy (anonymous):
at the start
OpenStudy (anonymous):
But all of the equations need time, how do you know what the time is?
OpenStudy (anonymous):
No sorry. at the start you are trying to throw it up. how would you have a zero speed at the beginning?
OpenStudy (anonymous):
ooh so the beginning it is 15m/s and at the highest point it is zero?
OpenStudy (anonymous):
actually. no tell me what is the equation of motion for such a problem?
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OpenStudy (anonymous):
DeltaX= VixT+.5xGxT^2
OpenStudy (anonymous):
OK, but you need time of flying which can be easily obtained by this relation:
|dw:1394135938489:dw|
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