Question

How many units apart are the points (4, -3) and (-4, 3)?

Answer 1

Use the distance formula

Answer 2

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ -3}})\quad &({\color{red}{ -4}}\quad ,&{\color{blue}{ 3}})
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

Answer 3

64+81 seems a lot for distance.

Answer 4

\[
\sqrt {(4-(-4))^2 + (3-(-3))^2 }=\sqrt{ 64+36}
\]

Answer 5

It is
\[
\sqrt{100}=10
\]

Answer 6

notice \(\bf \implies \sqrt{\qquad }\Longleftarrow\)

Answer 7

Oh ok. So it would be 10 units apart?