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How do you find dy/dx when ((lnx)+(lny^2)=3)? Thank you!
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i mainly don't understand how to find dy/dx of lny^2, the rest I believe I can do.
\[\ln x+\ln y^2=3,\ln x+2\ln y=3,differentiate~ with~ respect~ \to~ x\] \[\frac{ 1 }{x }+\frac{ 2 }{ y }\frac{ dy }{dx }=0\] now you can poceed.
THANK YOU! that was simpler than I thought.
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