Question

Domain of the inverse function of 6x+sqrt(x+37)?

Answer 1

I got [-222, infinity) but webassign says thats wrong?

Answer 2

Find the range of the function. that is the domain of the inverse function.

Answer 3

So, the lowest number I could get would be 6(-37) + sqrt(-37+37) right?

Answer 4

But, assuming my arithmetic is right, that's just -222 right?

Answer 5

yes

Answer 6

However, the domain is the set of x values. So the smallest member of the domain is -37

Answer 7

And the smallest member of the range is -222

Answer 8

And I used that for my answer, but its saying I got it wrong?

Answer 9

The exact problem, I may have misunderstood what they were asking or something.
Let f (x) = 6x + [sqrt]x + 37.

Choose the form of the largest interval on which f has an inverse
and enter the value(s) of the endpoint(s) in the appropriate blanks.
Then find (f −1)' (0).
Enter DNE in any unused answer blank.

Answer 10

I don't know what that means by choose the form of the interval

Answer 11

Here's a picture

Answer 12

The whole "form of the interval" is for closed brackets open brackets etc.

Answer 13

I see that and it seems like it should be -222

Answer 14

Alright. I guess it's just a mistake on my professor's part. I'll send them an email. Thanks for the help though.

Answer 15

It almost looks as if you - sign is too low. Perhaps you made a typo and typed _222 instead of -222. Is that possible?

Answer 16

Nah, I just double checked that, and it's just the font.

Answer 17

Sorry I can't help.

Answer 18

It's okay, thanks anyways.

Answer 19

http://www.wolframalpha.com/input/?i=domain+of+f%28x%29%3D%281%2F72%29%28-12x-1%29%2B-%281%2F72%29%E2%88%9A%2824x%2B5329%29

Answer 20

Alright, I'll try that

Answer 21

Yeah, that wasn't it