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Mathematics 19 Online
OpenStudy (anonymous):

Find the 11th partial sum of..

OpenStudy (anonymous):

OpenStudy (anonymous):

I didn't know how to write the equation out on here!

OpenStudy (anonymous):

add up the first 11 terms ...

OpenStudy (anonymous):

you can either brute math it, or use summation properties.

OpenStudy (anonymous):

-7(1) + 22 -7(2) + 22 -7(3) + 22 . . . -7(11) + 22 ------------------------ -7(1+2+3+...+11) + 22(11) all thats really 'hard' is knowing the sum of the digits from 1 to 11

OpenStudy (anonymous):

its simple enough to find 2times the sum, by adding it in a useful way: 1 + 2 + 3 + ... + 11 11 + 10 + 9 + ... + 1 -------------------- 12 + 12 + 12+ ... + 12 so we should be able to discern that the sum of 1 to 11 is equal to half of 11(12)

OpenStudy (anonymous):

\[11\left(-\frac{7(12)}{2}+22\right)\] i wonder if that can be remembered as a formula .. prolly not

OpenStudy (anonymous):

-220! Thanks :)

OpenStudy (anonymous):

youre welcome :)

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