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Mathematics 20 Online
OpenStudy (anonymous):

free medal for answer :D The number of members in a club dropped from 80 to 52. What is the percent of decrease in the number of members? A. 28% B. 35% C. 54% D. 65%

OpenStudy (anonymous):

A? Because if you subtract 52 from 80 you get 28..

OpenStudy (anonymous):

No, Rigsby. It's asking for the percent change.

OpenStudy (anonymous):

o.o already confusing

OpenStudy (anonymous):

So, Emily this is a much harder one and you probably wont be able to use my method.

OpenStudy (anonymous):

brb guys

OpenStudy (anonymous):

And since I'm unable to give you the answer I'll tell you how to solve it :)

OpenStudy (anonymous):

its 28%

OpenStudy (anonymous):

No it isn't.

OpenStudy (anonymous):

That's what I say @alyssa23

OpenStudy (anonymous):

And You're not allowed to give answers on this website, It's against the rules.

OpenStudy (anonymous):

It decreased by 28 people but not by 28% because it didn't start with 100 people.

OpenStudy (anonymous):

Maybe, you should try the formula. Try this 80-52/80

OpenStudy (anonymous):

and confused.

OpenStudy (anonymous):

Whoops.

OpenStudy (anonymous):

I meant (80-52)/80

OpenStudy (anonymous):

O.o

OpenStudy (anonymous):

@.@mathslover

OpenStudy (anonymous):

oops @.@ its a face

OpenStudy (anonymous):

Emily do you have a calculator You can use?

OpenStudy (anonymous):

So what he's saying is 80-52 = 28 and then divide 28 by 80.. That gives you 0.35 and if you put that in percentage, that's 35%..

OpenStudy (anonymous):

umm yea

OpenStudy (anonymous):

Yes, Correct Rigsby.

OpenStudy (anonymous):

Well if you do that equation it gives you the answer

OpenStudy (anonymous):

Works for almost all problems of this kind.

OpenStudy (anonymous):

soo 35%

OpenStudy (anonymous):

(first number-second number)divided by First number

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

michael give rigsby a medal for me kay?

OpenStudy (anonymous):

Mmk.

OpenStudy (anonymous):

Thanks (:

OpenStudy (anonymous):

Though she wouldn't of figured it out if it weren't for me :)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

But I'm glad to help. :)

OpenStudy (anonymous):

YOU DID LOL

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

This is almost like my refresher course, Going back remembering how to do all of this stuff :p

OpenStudy (anonymous):

lol

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