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Mathematics 21 Online
OpenStudy (anonymous):

A particle moves along the x-axis so that at any time t > 0 its velocity is given by v(t) = 10 – 3t2. If the particle is at position x = 8 at t = 1, what is the position of the particle at t = 3?

OpenStudy (anonymous):

you should integrate V(t), then you get X(t) .. it is then easy to find the answer...

OpenStudy (anonymous):

Integral of v(t) = 10 - 3t^2?

OpenStudy (anonymous):

yes..

OpenStudy (anonymous):

C - 3x^3 + 10x?

OpenStudy (anonymous):

no.. it must be in terms of time t.. not x

OpenStudy (anonymous):

Oh whoops I meant to write C - 3t^3 + 10t. Sorry

OpenStudy (anonymous):

@oksuz_ What do I do now?

OpenStudy (anonymous):

you should find what the C is .. you can use.. x=8, t=1

OpenStudy (anonymous):

So plug 1 into t?

OpenStudy (anonymous):

yes and 8 for x

OpenStudy (anonymous):

Where is x in the integral?

OpenStudy (anonymous):

not in the integral..it is result of the integral...

OpenStudy (anonymous):

ahhh I am so confused! :(

OpenStudy (anonymous):

x=10t-t^3 + C

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

have you found the answer ?

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