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A particle moves along the x-axis so that at any time t > 0 its velocity is given by v(t) = 10 – 3t2. If the particle is at position x = 8 at t = 1, what is the position of the particle at t = 3?
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you should integrate V(t), then you get X(t) .. it is then easy to find the answer...
Integral of v(t) = 10 - 3t^2?
yes..
C - 3x^3 + 10x?
no.. it must be in terms of time t.. not x
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Oh whoops I meant to write C - 3t^3 + 10t. Sorry
@oksuz_ What do I do now?
you should find what the C is .. you can use.. x=8, t=1
So plug 1 into t?
yes and 8 for x
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Where is x in the integral?
not in the integral..it is result of the integral...
ahhh I am so confused! :(
x=10t-t^3 + C
Thank you!
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yw
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