Find consecutive integers between which the square root lies.

Question

jjuden · Answer

$$\sqrt{111}$$

jjuden · Answer

these r my choices  
       20 and 22
       10 and 11
       5 and 6
       4 and 5

mathmale · Answer

Why not experiment by finding the squares of several integers?  Look for squares that are just larger than 111 or just smaller than 111.

For example, the square of 8 is 64, but 64 is a lot smaller than 111, isn't it?
Another ex.:  the square of 12 is 144, but that's a lot larger than 111, isn't it?
So, 8 is too small and 12 too large.  Try again:  choose the next consecutive integer following 8 and the previous consecutive integer preceding 12.  Eventually you will find the 2 consecutive integers between which Sqrt(111) lies.  Good luck.

mathmale · Answer

@jjuden ?

jjuden · Answer

what

mathmale · Answer

I'm hoping that you'll finish this problem.