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OpenStudy (anonymous):
Multiply (5x^2+x-4)(x+2)
A.5x^3+x^2-4x-8
B.5x^3+11x^2-2x-8
C.5x^3+10x^2-4x-8
D.5x^3+20x^2+2x-8
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OpenStudy (anonymous):
i dont understand how to foil this prob with the three numbers in the first part of the equation
OpenStudy (anonymous):
(5x^2+x-4)(x+2)
(5x^2)(x) + (5x^2)(2) will be the product of 5x^2. Do you see the pattern here? It works the same for the other two numbers.
OpenStudy (anonymous):
not really how is (5x^2)(x)+(5x^2)(2) the product of 5x^2
OpenStudy (anonymous):
Because of (x+2). You cannot multiply (x+2) with 5x^2 at once, so you have to separate x and 2.
Sorry, I had to say product of 5x^2 and (x+2).
OpenStudy (anonymous):
im very confused????
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OpenStudy (anonymous):
Umm.. Okay.
Do you know how to solve
5(x+2) ?
OpenStudy (anonymous):
5x+10
OpenStudy (anonymous):
How about 5x^2(x+2)?
Use the same method that you used for solving 5(x+2).
OpenStudy (anonymous):
5x^2+100?
OpenStudy (anonymous):
5x^2 * x = 5x^3
5x^2 * 2 = 10x^2
Do you see why?
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OpenStudy (anonymous):
yeaah bcuz the x turns the ^2to ^3 and 5 times 2 equals 10
OpenStudy (anonymous):
Right??
OpenStudy (anonymous):
Yup! :)
OpenStudy (anonymous):
Now you can the same thing for x and -4.
OpenStudy (anonymous):
so 5x^2 times x would be 5x^3 and -20x^2 correct???
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OpenStudy (anonymous):
The answer is correct. :D
But I was talking about 'x' and '-4' of (5x^2+x-4).
OpenStudy (anonymous):
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