Question

Determine the number and type of complex solutions and possible real solutions for each of the following problems.

1) 2x2 + 5x + 3 = 0

2) 4x3 – 12x + 9 = 0

3) 2x4 + x2 – x + 6 = 0

Answer 1

2x^2 + 5x + 3 = 0
(x+1) (2 x+3) = 0
x = -1 or x = -3/2

Answer 2

do you understand why?

Answer 3

I'm still confused on the topic....

Answer 4

ok, this is what's called a quadratic equation
2x^2 + 5x + 3 = 0

there are generally 2 ways to solve
for the easy ones: factorization, so breaking it up into
(this) times (that) = 0
in this case, it can be broken down to
(x+1) (2x+3) = 0
its the reverse of the FOIL technique
so now u have
(this) times (that) = 0
(x+1)times (2x+3) = 0
so to get 0, either (x+1) = 0 or (2x+3) = 0

Answer 5

does that make sense so far?

Answer 6

so does the above make sense @menosleep ?