What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)?

y − 1 = −2(x − 4)

y − 1 = 2(x + 2)

y − 13 = −2(x + 2)

y − 13 = 2(x + 4)

Question

What is the equation in point-slope form of the line passing through (−2, 1) and (4, 13)?

 y − 1 = −2(x − 4)

 y − 1 = 2(x + 2)

 y − 13 = −2(x + 2)

 y − 13 = 2(x + 4)

anonymous · Answer

y − 1 = 2(x + 2)

anonymous · Answer

by two point form
as if we have point let (a,b) and (c,d)
then equation of line is 
(y-b)=((b-d)/(a-c))(x-a)
so here (-2,1) and (4,13)
y-1=((1-13)/(-2-4))(x-(-2))
=> y-1=2(x+2)