Question

Find all solutions in the interval [0, 2π).

4 sin2 x - 4 sin x + 1 = 0

Answer 1

can you factor 4u^2 - 4u + 1 = 0?

Answer 2

(2x-1)^2

Answer 3

good. But don't use x. Use a different letter.
What do you think 4sin^2(x) - 4sin(x) + 1 is in factor form?

Answer 4

So.. (2sin x -sin x)^2?

Answer 5

I will be back in 20.

Answer 6

I'm back @sourwing !

Answer 7

Hello? Oh, and it should have been: (2sin x-1)^2. My bad.

Answer 8

good
(2sinx - 1)^2 = 0
what would you do next?

Answer 9

For these questions what I personally like to do is let sin x=m and the equation will become: 4m^2+4m+1=0
It's a quadratic equation! Just remember to change it back to sin afterwards :)