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OpenStudy (anonymous):
please help me... what is the polar form of (x+y)^2 = x-y ?
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OpenStudy (anonymous):
put x = r cos theta and y = r sin theta you will find it equal to a polar form.
OpenStudy (anonymous):
(rcostheta + rsintheta)^2 = r(costheta - sintheta) is the final answer?
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