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Mathematics
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OpenStudy (anonymous):
Rewrite with only sin x and cos x.
sin 3x - cos x
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OpenStudy (cwrw238):
Hint sin2x = 2sinxcosx
OpenStudy (anonymous):
Can you help me? This confuses me too much
OpenStudy (cwrw238):
how far have you got with trigonometry?
OpenStudy (cwrw238):
sorry i have to go now
OpenStudy (anonymous):
do you know any trig identities for multiple of an angle?
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OpenStudy (anonymous):
here is the one that is worth memorizing:
sin(3x) = -4sin^3(x) + 3sin(x)
OpenStudy (anonymous):
Okay an you help me solve this
OpenStudy (anonymous):
@sourwing
OpenStudy (anonymous):
you're practically done.
sin(3x) - cos(x) = sin(3x) = -4sin^3(x) + 3sin(x) - cos(x)
OpenStudy (anonymous):
A. 2 sin x - sin^3 x - cos x
B. 2 sin x cos^2 x + sin x - 2 sin ^3 x - cos x
C. 2 sin^3 x cos^4 x + 1
D. 3 sin x cos x - sin^3 x - cos x
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OpenStudy (anonymous):
I think it's D @sourwing
OpenStudy (cwrw238):
sin3x = sin(2x + x) = sin2xcosx + sinxcos2x
= 2sinxcos^2x + sinx( cos^2x - sin^2x)
= 2sinxcos^2x + sinxcos^2x - sin^3x
= 3sinx cos^2x - sin^3x
sin3x - cosx = 3sinx cos^2x - sin^3x - cosx
OpenStudy (cwrw238):
- that result works though its not exactly = D
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