Can someone tell me the x intercept, y intercept, line of symmetry, and vertex please for the equation x^2+4x+4

Question

anonymous · Answer

You cannot have an exponent in y intercept form. so you will have to work it another way. That is all I knowl

whpalmer4 · Answer

This is a parabola.  The line of symmetry in a parabola goes through focus, vertex, and is perpendicular to directrix.  

The vertex for a parabola in the form $$y=ax^2+bx+c$$has an x-value of $x=-\dfrac{b}{2a}$  The y-value can be found by evaluating the equation at that value of $x$.

The y-intercept is simply the value of $y$ where $x = 0$.  Substitute $x=0$ and evaluate to find the y-intercept.

The x-intercepts (if any) are the values of $x$ where $y=0$.  Use the quadratic formula, or complete the square, or factor, or whatever your favorite method is for solving finding the solutions to quadratic equations.