A 10-Meter cable is needed to support a load of 50,000 N. The deflection under this load must be less than 5mm and, it should not yield. What cable mass is necessary in this situation for

a) low-carbon steel, density=7800kg/m^3 and E=2.07x10^11 Pa
B) wrought aluminum alloy, density=2800kg/m^3 and E=.69x10^11 Pa?

Question

A 10-Meter cable is needed to support a load of 50,000 N. The deflection under this load must be less than 5mm and, it should not yield. What cable mass is necessary in this situation for 

a) low-carbon steel, density=7800kg/m^3 and E=2.07x10^11 Pa
B) wrought aluminum alloy, density=2800kg/m^3 and E=.69x10^11 Pa?

anonymous · Answer

Is it assumed the cable is stretched horizontally? Supports mass at midpoint?

anonymous · Answer

it is supported in the y vertically.

anonymous · Answer

You want less than 0.005m/10 m deflection/extension.
You have 50,000 N to be supported by the cable cross-section A.
The mass of the wire will be (density)(A)(length).
The modulus of elasticity gives the stress (tension force/A) per 100% extension (strain).
Presumably you are to calculate the masses for each cable material.