What is the area of a rectangle with the width of 25" and the angle between the width and the diagonal measuring 38*? @jigglypuff314 this one really confuses me
first of all what is the " i never memorized that
the star is degrees *
the " is inches
thank you
yeah, so we have |dw:1394415195635:dw|
area = width times length so we need to find length what trig function could we use that would be opposite and adjacent ?
TOA
yes :) so we would use tangent tan(angle) = (opp/adj) angle = 38 opp = ? adj = 25 plug in what you know so tan(38) = ? / 25 (multiply both sides by 25 to get ? by itself) so ? = 25 tan(38)
wait im confused on how to plug in the ?/25
? = 25 tan(38) plug in 25 times tan(38)
Oh ok its just i get confused when they put the equation tan38=x/25 so the only thing to put in is 25xtan38 and then its 19.53
19.53 is correct :)
YAY
i realized that you missed a step but i think i figured it out
cuz on a problem my teacher multiplied it by the width at the end after the angle measure so it be 25xtan38x25
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