What is the area of a rectangle with the width of 25" and the angle between the width and the diagonal measuring 38*? @jigglypuff314 this one really confuses me
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OpenStudy (elisaneedshelp):
first of all what is the " i never memorized that
OpenStudy (elisaneedshelp):
the star is degrees *
OpenStudy (nikato):
the " is inches
OpenStudy (elisaneedshelp):
thank you
jigglypuff314 (jigglypuff314):
yeah, so we have |dw:1394415195635:dw|
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jigglypuff314 (jigglypuff314):
area = width times length
so we need to find length
what trig function could we use that would be opposite and adjacent ?
OpenStudy (elisaneedshelp):
TOA
jigglypuff314 (jigglypuff314):
yes :)
so we would use tangent
tan(angle) = (opp/adj)
angle = 38
opp = ?
adj = 25
plug in what you know
so tan(38) = ? / 25 (multiply both sides by 25 to get ? by itself)
so ? = 25 tan(38)
OpenStudy (elisaneedshelp):
wait im confused on how to plug in the ?/25
jigglypuff314 (jigglypuff314):
? = 25 tan(38)
plug in 25 times tan(38)
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OpenStudy (elisaneedshelp):
Oh ok its just i get confused when they put the equation tan38=x/25 so the only thing to put in is 25xtan38 and then its 19.53
jigglypuff314 (jigglypuff314):
19.53 is correct :)
OpenStudy (elisaneedshelp):
YAY
OpenStudy (elisaneedshelp):
i realized that you missed a step but i think i figured it out
OpenStudy (elisaneedshelp):
cuz on a problem my teacher multiplied it by the width at the end after the angle measure so it be 25xtan38x25