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Trigonometry 17 Online
OpenStudy (elisaneedshelp):

What is the area of a rectangle with the width of 25" and the angle between the width and the diagonal measuring 38*? @jigglypuff314 this one really confuses me

OpenStudy (elisaneedshelp):

first of all what is the " i never memorized that

OpenStudy (elisaneedshelp):

the star is degrees *

OpenStudy (nikato):

the " is inches

OpenStudy (elisaneedshelp):

thank you

jigglypuff314 (jigglypuff314):

yeah, so we have |dw:1394415195635:dw|

jigglypuff314 (jigglypuff314):

area = width times length so we need to find length what trig function could we use that would be opposite and adjacent ?

OpenStudy (elisaneedshelp):

TOA

jigglypuff314 (jigglypuff314):

yes :) so we would use tangent tan(angle) = (opp/adj) angle = 38 opp = ? adj = 25 plug in what you know so tan(38) = ? / 25 (multiply both sides by 25 to get ? by itself) so ? = 25 tan(38)

OpenStudy (elisaneedshelp):

wait im confused on how to plug in the ?/25

jigglypuff314 (jigglypuff314):

? = 25 tan(38) plug in 25 times tan(38)

OpenStudy (elisaneedshelp):

Oh ok its just i get confused when they put the equation tan38=x/25 so the only thing to put in is 25xtan38 and then its 19.53

jigglypuff314 (jigglypuff314):

19.53 is correct :)

OpenStudy (elisaneedshelp):

YAY

OpenStudy (elisaneedshelp):

i realized that you missed a step but i think i figured it out

OpenStudy (elisaneedshelp):

cuz on a problem my teacher multiplied it by the width at the end after the angle measure so it be 25xtan38x25

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