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Write a rule for the nth term of the geometric sequence. Find a6. Then grapth the first five terms of the sequences r=3, a1=2
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@douglaswinslowcooper
\[a,ar,ar^2,ar^3,ar^4,...\] \[2,2\times 3,2\times 3^2,2\times 3^3,2\times 3^4,...\] is what this looks like general term is \(a_n=2\times 3^{n-1}\)
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@ganeshie8
As @satellite73 indicated , the first term will be a1 = 2, and the next ones will be a2=(a1)(3) = 6, a3=(a2)(3)= (a1)(3)^2= (2)(9) =18 an = (a1)(3)^(n-1) = (2)(3)^(n-1)
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so thats the answer? how about the graphing part
Do you know how to plot graphs?
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