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Find y. \[\frac{ dy }{ dx } = (\cos x )e^{y+\sin x}\]
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e^(y + sinx) = e^y * e^sinx. It now becomes separable
ah ty.
dy e^-y=cos x e^sin x dx
\[\int\limits_{}^{} \frac{ 1 }{ e^y } dy = \int\limits_{}^{} (\cos x) e^{\sin x} dx\]
got it from here, ty.
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