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Mathematics 13 Online
OpenStudy (hanner_b_nanner):

WILL GIVE MEDAL!!! I did the first part, but I'm confused on the second part of the question... Can someone please HELP? Triangle LMN is located at L (2, 3), M (1, 2), and N (4, 4). The triangle is then transformed using the rule (x+5, y+2) to form the image L'M'N'. What are the new coordinates of L', M,' and N'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

OpenStudy (anonymous):

i am sorry i would help but i cant i have a horrible math grade wish i could help more :'(

OpenStudy (hanner_b_nanner):

it's ok, thanks though! :)

OpenStudy (johnweldon1993):

Well...You have the 3 points.. L(2,3) M(1,2) N(4,4) The translation is (x + 5, y + 2) This means that for each point you have in the form (x , y) you would just add 5 to the x coordinate...and 2 to the y coordinate... So for example... L(2,3) would become L'(2 + 5 , 3 + 2) ...L'(7 , 5) Does that make sense?

OpenStudy (hanner_b_nanner):

Yes, I did that part already :) ... The new coordinates of L', M', and N' will change by adding (x+5, y+2) to the original values of the points. L' (2, 3)- 2+5, 3+2= (7, 5) M' (1, 2)- 1+5, 2+2= (6, 4) N' (4, 4)- 4+5, 4+2= (9, 6) But I don't know what it means by the characteristics of the corresponding vertices...

OpenStudy (johnweldon1993):

Alright so think about it like this... What we HAD Triangle LMN was something like |dw:1394470905004:dw|

OpenStudy (johnweldon1993):

Now what we HAVE L'M'N' is |dw:1394471017923:dw| That top one (for the most part, I ran out of room

OpenStudy (johnweldon1993):

And if we connect the corresponding vertices we will have |dw:1394471090233:dw| What looks like a triangular prism

OpenStudy (hanner_b_nanner):

ohhh, okay. So I need to describe the lines that are drawn between the two figures... you were a HUGE help! Thanks! :)

OpenStudy (johnweldon1993):

Right....you would basically here say that if you connect the corresponding vertices of the 2 triangles you would then get a triangular prism... No problem :)

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