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Mathematics 16 Online
OpenStudy (vshiroky):

Please help :)

OpenStudy (vshiroky):

@nuz93 do you know how to do this?

OpenStudy (vshiroky):

I got 19x=0 so x=0?

OpenStudy (vshiroky):

and y=-4?

OpenStudy (ikram002p):

i got the same :)

OpenStudy (vshiroky):

Ok and how would I graph it?

OpenStudy (vshiroky):

I know (0,-4) but how would I get the other point to make my line?

OpenStudy (ikram002p):

4x-3y=12 5x+y=-4 |dw:1394477105406:dw|

OpenStudy (vshiroky):

How did you get the second point?

OpenStudy (vshiroky):

up 4 over 3? slope intercept?

OpenStudy (anonymous):

theres one similar question u've workd on some days ago? right?

OpenStudy (ikram002p):

|dw:1394477203360:dw|

OpenStudy (anonymous):

yeah the point of intersection is the answer

OpenStudy (vshiroky):

The second line is just up 4 over 1?

OpenStudy (ikram002p):

well draw each line alone , for first line 4x-3y=12 when x=0 , y= 4 when y=0 ,x=3 so drow it using two ponits (0,4) (3,0)

OpenStudy (vshiroky):

Or would it be up 5 over 1?

OpenStudy (vshiroky):

I put the 2 in slope intercept y=4/3x-4 y=-5x-4

OpenStudy (ikram002p):

then draw the second line 5x+y=-4 when x=0 , y=-4 when y=0 , x= -4/5 so also draw it using two points (0,-4) (-4/5 ,0)

OpenStudy (ikram002p):

after drowing the two lines the point of intersecting is the solution , got it nw ?

OpenStudy (vshiroky):

No lol

OpenStudy (vshiroky):

Ill show you my graph

OpenStudy (ikram002p):

ok show me

OpenStudy (vshiroky):

OpenStudy (ikram002p):

its correct ! and its the same for what i draw :P

OpenStudy (vshiroky):

Woo thanks!!!

OpenStudy (ikram002p):

np :D

OpenStudy (vshiroky):

I'm going to be opening another that I am confused on. Can I tag you?

OpenStudy (ikram002p):

yes sure :)

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