Mathematics
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OpenStudy (vshiroky):
Please help :)
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OpenStudy (vshiroky):
@nuz93 do you know how to do this?
OpenStudy (vshiroky):
I got 19x=0 so x=0?
OpenStudy (vshiroky):
and y=-4?
OpenStudy (ikram002p):
i got the same :)
OpenStudy (vshiroky):
Ok and how would I graph it?
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OpenStudy (vshiroky):
I know (0,-4) but how would I get the other point to make my line?
OpenStudy (ikram002p):
4x-3y=12
5x+y=-4
|dw:1394477105406:dw|
OpenStudy (vshiroky):
How did you get the second point?
OpenStudy (vshiroky):
up 4 over 3? slope intercept?
OpenStudy (anonymous):
theres one similar question u've workd on some days ago? right?
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OpenStudy (ikram002p):
|dw:1394477203360:dw|
OpenStudy (anonymous):
yeah the point of intersection is the answer
OpenStudy (vshiroky):
The second line is just up 4 over 1?
OpenStudy (ikram002p):
well draw each line alone , for first line
4x-3y=12
when x=0 , y= 4
when y=0 ,x=3
so drow it using two ponits (0,4) (3,0)
OpenStudy (vshiroky):
Or would it be up 5 over 1?
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OpenStudy (vshiroky):
I put the 2 in slope intercept
y=4/3x-4
y=-5x-4
OpenStudy (ikram002p):
then draw the second line
5x+y=-4
when x=0 , y=-4
when y=0 , x= -4/5
so also draw it using two points
(0,-4) (-4/5 ,0)
OpenStudy (ikram002p):
after drowing the two lines the point of intersecting is the solution , got it nw ?
OpenStudy (vshiroky):
No lol
OpenStudy (vshiroky):
Ill show you my graph
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OpenStudy (ikram002p):
ok show me
OpenStudy (vshiroky):
OpenStudy (ikram002p):
its correct !
and its the same for what i draw :P
OpenStudy (vshiroky):
Woo thanks!!!
OpenStudy (ikram002p):
np :D
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OpenStudy (vshiroky):
I'm going to be opening another that I am confused on. Can I tag you?
OpenStudy (ikram002p):
yes sure :)