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OpenStudy (anonymous):
Use the discriminant to describe the roots of each equation. Then select the best description.
1. x^2 - 5x + 7 = 0
2. x^2 - 5x - 4 = 0
3. 16x^2 + 8x + 1 = 0
4. x^2 + 9x + 14 = 0
3 minutes agoEdit Question
here are the options
a.double root
b.real and rational root
c.real and irrational root
d.imaginary root
12 years ago
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OpenStudy (anonymous):
@mathstudent55 can you help?
12 years ago
OpenStudy (anonymous):
Do you know what to find the discriminant?
12 years ago
OpenStudy (anonymous):
no can you show me how to do 3 i figured out 1&2
12 years ago
OpenStudy (anonymous):
\[
16x^2 + 8x + 1 = (4 x+1)^2=0\\
x=-\frac 14
\]
double roots
12 years ago
OpenStudy (anonymous):
\[
b^2 - 4 a c = 64 - 4(16)1=0
\]
double roots
12 years ago
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OpenStudy (anonymous):
Do you understand it? I did it in two ways.
12 years ago
OpenStudy (anonymous):
what about #5?
12 years ago
OpenStudy (anonymous):
There is no number 5
12 years ago
OpenStudy (anonymous):
oh hah well what about this one?
2 = x^2 + 5x
12 years ago
OpenStudy (anonymous):
\[2 = x^2 + 5x\\
x^2 + 5 x -2=0\\
b^2-4ac= 25 +8=33
\\
\text { 33 is not a perfect square. Hence roots are irrationals }
\]
12 years ago
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OpenStudy (anonymous):
i got a few more...what about this one?
2m^2 + 3 = m
12 years ago
OpenStudy (anonymous):
I think, you should ask each question as a new problem, to avoid confusion for other students.
12 years ago
OpenStudy (anonymous):
Okay thanks anyway
12 years ago
OpenStudy (anonymous):
YW
12 years ago
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