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There is a 25ft ladder leaned 7ft away from a building if the top of the ladder slips down 4ft, how many feet will the bottom slide out?
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Draw a picture: |dw:1394495341625:dw|
4 ft?
|dw:1394495381097:dw| By Pythagorean theorem, we have \[7^2 + x^2 = 25^2\] The ladder stays the same length when the height along the wall goes from \(x\) to \(x-4\). That means that the bottom leg is now (7+y) and\[(x-4)^2 + (7+y)^2 = 25^2\]
If you like, you can solve for the value of \(x\) before attempting to find \(y\).
In fact, you probably should :-)
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oh my bad its 8 ft
Yes, that's correct.
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