I have this question that i am stuck with for the past 20 mins so I was thinking someone could help me so the question is below. Which of the following is NOT a solution of y=5x - 10 ? A. 5,20 B. 3,5 C. 4,10 D. 2.0
In D. i meant 2,0
plug in each of the values in the format (x,y) into the equation
ummm I am in 6th grade and I have no idea how to do that!
I typed what ASNinja typed but my message did not post. :(
But...
I don't know how to do that i only am in 6th grade even my parents don't know how to do this!
Okay so the first answer (A) is the points 5 and 20 correct?
correct
so each of the answer choices are in the format (x,y) so plug in each value into the equation for A 20 = 5(5) -10 \[20 \neq 15\]
So in the equation, there is an x and a y. (5, 20) are the x and the y. 5 is the x and 20 is the y.
x always comes 1st right?
Yes
yes, (x, y)
Thank you
You're welcome
I still don't know how to get the answer
Which of the choices when plugged into the equation is false?
ASNinja will probably explain it better than me.
Err i dont know
But there is nothing that tells me what y or x is
We just plugged in A, and got that 20 = 15
Wait a minute I think I understand now
Is that a true statement? Do you know what coordinates are?
The 1st number which is X i plug that in and the 2nd number is y so if i plug in X and solve it then Y is the answer.
Yup I got it thank you!
yes, but if we plug in the values for A, it doesn't work, so the correct answer is A
Yes i got the same answer right now!
Also i have a question
How do you graph an equation?
Not the one with slope
Give me an example
Ok
how do you graph y=x+3
That equation has a slope of 1 so, |dw:1394502064555:dw|
But not the 1 with slope
the one i have to do is different
The equation you gave me has a slope of 1
y = 1x + 3
Khan's videos might be helpful. For example, see http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/graphing-slope-intercept/v/graphing-a-line-in-slope-intercept-form on one way to plot lines.
Yeah. Take a look at KhanAcademy.org
here is another way http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/graphing_solutions2/v/plotting--x-y--relationships
Did you solve the problem?
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