Question

Help ASAP
For the simple harmonic motion equation d=2sin(pi/3)t , what is the period?

Answer 1

? that simplifies to \[d=t(\sqrt{3})\] so its just a line

Answer 2

@Angela2014 :
Could you be clearer in presenting this problem?
Do you mean \[d=2\sin(\frac{ \pi*t }{ 3 })?\]

Answer 3

its actually d=5sin(2pi t)

Answer 4

@mathmale

Answer 5

Looks as though you're working on two different problems in the same post. Please choose the one you want to focus on.

Answer 6

The one i commented is the actual problem the first one was a typo.
i need
d=5sin(2 pi t)

Answer 7

@mathmale

Answer 8

\[d=5\sin(2\pi t)\]

Answer 9

The general rule for finding the period is this:\[Period=\frac{ 2\pi }{ b }\] where b is the coefficient of the variable t in your function
\[d=2\sin(2\pi*t)\] What is that coefficient? What is the period, then?

Answer 10

I have no idea

Answer 11

What does "coefficient" mean?

Answer 12

What you multiply

Answer 13

Do you have an algebra book handy? You need a better definition of "coefficient," specifically, a definition of what "coefficient" means in the context y=2sin[2pi*t].

Answer 14

I don't actually. I'm taking a pre cal course online and it is very hard and im horrible in math

Answer 15

I hope you're willing to look up things that you don't know. Doing so may take some effort now, but will reward you in the long run because you'll have a better understanding of math terminology.

Do you have a Pre-Calc textbook?

If not, what is your primary reference source?

Answer 16

In your expression, \[d=2\sin (2\pi*t)\] the "coefficient" is just the constant (2Pi) that multiplies your variable (t).

Let's call that coefficient " b "

Then the period is \[Period=\frac{ 2\pi }{ b }\]

Please substitute that b value into this formula for period and find the period.