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if Sin(theta) = 4/5 and is in the second quadrant, the value of cos(theta) is?
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In the 2nd quadrant, sin and csc are positive. Therefore, cosine is negative
Draw a triangle, using the definition of sine
Oh Okay Thanks ^^ much appreciated I was over thinking
|dw:1394592060233:dw| Find side b, then find use the definition of cosine to find the cosine *Oops, let me fix the drawing, one side should be negative
*never mind, only side b is negative. I 2nd guessed myself
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I see, but going off the rule it would be 3 right however since it is in Quadrant 2 it would be negative right?
5^2 = 4^2 + x^2 Yes, side b would be -3 Now what is the cosine?
-3/5
Yes, -3/5
Thank you ! ^^
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