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Find the first five terms of the geometric sequence for which a1= 3 and r=-2?
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\[a_{n} = a_{1}*r^{n-1}\]
i dont know how to find n
n is the number of the term you're finding.
oh!
You already know that a1 = 3, so the next one you want is a2 where n = 2.
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So as an example, \[a_2 = 3 * -2^{2-1} = -6\] And this just needs to be repeated until you get to 5.
is \[a _{3}=12?\]
Yes.
so 3, 6, 12, 24, 48?
Don't forget about the negative sign on r.
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did i do it wrong?
It should be 3, -6, 12, -24, 48 because r=-2, not just 2.
oh!
thanks i have more questions still haha..
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