Question

expand the series 6 over sigma, k-2 under sigma (-1) ^k (7-k) k

Answer 1

Is this what you meant?
\[\sum^6_{k=2} (-1)^{k} (7-k) k\]

Answer 2

yes .

Answer 3

All you need to do, Junior, is to let k=2, 3, 4, 5, and so on (just a few examples) and to calculate the corresponding value of (-1)^k * (7-k)k. Write out the first few terms. That's it.

Answer 4

You should get \(6\) as your answer if you add the terms properly.

Answer 5

Thank you !