James jumped off a cliff into the ocean in Acapulco while vacationing with friends. His height as a function of time is modeled as: h(x)=-16t^2+16t+480 t is time (seconds) and h is height (feet) How long did it take James to reach Max height? I definitely need help with this
Ok our equation is in standard form \[ax^2+bx+c\] Where our a=-16, b=16 and c=480 Our maximum point occurs at the vertex We know that the x coordinate of our vertex can be found using the following equation \[\frac{-b}{2a}\] Using this equation what would our x-coordinate of our vertex be?
\[\frac{ 1 }{ 2 }\]
So now we have found that the vertex occurs at t=1/2 or in other words at a half a second we reach the maximum height. Now in order to find the height we need to plug into our equation t=1/2 and we will find the maximum height.
How would you go about finding how long it took for James to hit the water?
Ok when you hit the water the height is 0 So plug in 0 as height and then solve for t to find at the time you hit the water
Oh yeah!! Duh lol I'm so sleepy xD Thanks mate!
Same here. I can barely function. Not sure why I am on here
Haha
Join our real-time social learning platform and learn together with your friends!