Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

James jumped off a cliff into the ocean in Acapulco while vacationing with friends. His height as a function of time is modeled as: h(x)=-16t^2+16t+480 t is time (seconds) and h is height (feet) How long did it take James to reach Max height? I definitely need help with this

OpenStudy (anonymous):

Ok our equation is in standard form \[ax^2+bx+c\] Where our a=-16, b=16 and c=480 Our maximum point occurs at the vertex We know that the x coordinate of our vertex can be found using the following equation \[\frac{-b}{2a}\] Using this equation what would our x-coordinate of our vertex be?

OpenStudy (anonymous):

\[\frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

So now we have found that the vertex occurs at t=1/2 or in other words at a half a second we reach the maximum height. Now in order to find the height we need to plug into our equation t=1/2 and we will find the maximum height.

OpenStudy (anonymous):

How would you go about finding how long it took for James to hit the water?

OpenStudy (anonymous):

Ok when you hit the water the height is 0 So plug in 0 as height and then solve for t to find at the time you hit the water

OpenStudy (anonymous):

Oh yeah!! Duh lol I'm so sleepy xD Thanks mate!

OpenStudy (anonymous):

Same here. I can barely function. Not sure why I am on here

OpenStudy (anonymous):

Haha

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!