Question

solving this quadratic equation by factoring
(x+1)(2x-3)=8(2x-3)

Answer 1

is this the question or you stuck here???

Answer 2

im stuck on this question...but the topic is called "solving quadratic equations by factoring

Answer 3

when you will see the discriminant, it is less than 0.
so it can not be factorize|
it has complex solutions.

Answer 4

so than wat do I do? :(

Answer 5

you can find the answer by this formula

Answer 6

have you studied complex numbers???

Answer 7

nope :(

Answer 8

oh i made a mistake
the answer is x=3/2 and 7

Answer 9

(x+1)(2x-3)=8(2x-3)
2x^2 -3x+2x-3=16x-24
2x^2 -x-3-16x+24=0
2x^2 -17x+21=0
2x^2-14x-3x+21=0
2x(x-7)-3(x-7)+0
(2x-3)(x-7)=0
x=(3/2) and x=7

Answer 10

thankxxxxx

Answer 11

@RebeL_NYC :-)

Answer 12

how bout xsquared=81

Answer 13

+9 ans -9