can any one help
Here you go.
Thank u a lot @Issy14
You are welcome, anytime.!=)
Can u help with algebra I have a question ?? @Issy14
go ahead
H(x)= 2x^2-12x+18 Find the zeros of each function by factoring @Issy14
1 sec
ok, this is what I got. 2x^2 - 12x + 18 = 0 Factor: 2(x^2 -6x +9)=0 Factor: (x-3)(x-3)=0 When x = 3 the equation = 0.
Ohh ok thanks
But where did the 2 go 2(x^2-6x+9)=0
@Issy14
Ok, so as you factorize, the objective is basically to make it smaller, to get to the simplest terms. Therefore, the 2 is just the common factor from the original equation. the ( x^2-6x+9) is your new equation, that's what you are going to work from now on. I found a good website for you: http://www.wikihow.com/Find-the-Zeros-of-a-Function
Thanks a lot I have a question can I ask ?
Yup
Find the root of each equation by factoring X^2=49
7
Oh so square root of 49
Another one sorry I'm asking a lot 5x^2+20=20x Find the square root by factoring
Same concept as the first one: 1- Equal the equation to 0. 5x^2-20x+20=0 2. Find the common factor: 5(x^2 -4x +4)=0 3. Keep factoring: (x-2)(x-2)
Why does 20 become + not -
It has to become 5x^2-20x-20
@Issy14
because when you move a number from side of the equation to the other side it goes from doing the opposite of the original.
Since 20x was positive it went to being negative. or from adding to substracting
5x^2-20x+20=0 Ya here it has to be -
-20
@issy14
You are not moving the 20, therefore, it stays positive
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